Answer:
c
Step-by-step explanation:
Let 1/x = a &
1/y = b
So, now the equation:
2a +3b = 13 --------------------(i)
5a - 4b = -2 --------------------(ii)
To eliminate a, Multiply equation (i) by 5 and multiply (ii) by (-2)
(i)*5 10a + 15b = 65
(ii)*(-2) <u> - 10a + 8b = 4</u> ( Now add, a will be eliminated}
23b = 69
b= 69/23
b = 3
Plug in the value of b in equation (i)
2a + 3*3 = 13
2a + 9 = 13
2a = 13 - 9
2a = 4
a= 4/2
a = 2
Now a = 1/x ------>x = 1/a = 1/2
b = 1/y ----------->y = 1/b = 1/3

Answer:
two bananas because he's a monkey
Step-by-step explanation:
Answer:
I can. I'm great at math and science.
Step-by-step explanation:
2 and 3.
Answer:
c or 3rd one
Step-by-step explanation:
![\bf ~\hspace{10em}1\le x\le 5~\hspace{5em}\sqrt{x^3+36} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{x^3+36}\implies \sqrt{x^{2+1}6^2}\implies \sqrt{x^2x6^2}\implies \sqrt{(6x)^2x}\implies 6x\sqrt{x} \\\\\\ \stackrel{\textit{x = 4}}{6(4)\sqrt{4}}\implies 24\sqrt{2^2}\implies 24\cdot 2\implies 48](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B10em%7D1%5Cle%20x%5Cle%205~%5Chspace%7B5em%7D%5Csqrt%7Bx%5E3%2B36%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Csqrt%7Bx%5E3%2B36%7D%5Cimplies%20%5Csqrt%7Bx%5E%7B2%2B1%7D6%5E2%7D%5Cimplies%20%5Csqrt%7Bx%5E2x6%5E2%7D%5Cimplies%20%5Csqrt%7B%286x%29%5E2x%7D%5Cimplies%206x%5Csqrt%7Bx%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7Bx%20%3D%204%7D%7D%7B6%284%29%5Csqrt%7B4%7D%7D%5Cimplies%2024%5Csqrt%7B2%5E2%7D%5Cimplies%2024%5Ccdot%202%5Cimplies%2048)
that's how I read it.... to get some value between 1 and 5, namely 4, to make the expression a rational, well, 48 can be expressed as 48/1.