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kondaur [170]
3 years ago
8

Need Help REALLY REALLY REALLY BADLY! Lol Hi :) I really need help with this statistics question within 10 minutes. I do not kno

w where to start and math is not my strong suit. I don't even know where to start so your help would be greatly appreciated <3 this is worth 20 points!
Andrew believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request. He asked 500 students at his school the following questions: "Are you on the honor roll?" and "Did you get the math class you requested?" The results are shown in the table below:

Honor roll Not on honor roll Total
Received math class requested 215, 125, 340,
Did not get math class requested 80, 80, 160
Total 295, 205, 500
Help Andrew determine if all students at his school have an equal opportunity to get the math class they requested. Show your work and explain your process for determining the fairness of the class assignment process.
Mathematics
1 answer:
lyudmila [28]3 years ago
4 0
The key to this question is calculating the percentage of students within each category (honor roll or non-honor roll) who received the class requested. We need to calculate the ratio of students who received the class they requested and who did not for both honor roll and non-honor roll students :

Honor Roll :

215 + 80 = 295 total honor roll students 

215/295 = 72.88% = percentage of honor roll students who received class requested

80/295 = 27.12% = percentage of honor roll students who did not receive class requested

Non-Honor Roll :

125 + 80 = 205 total non-honor roll students 

125/205 = 60.98% = percentage of non-honor roll students who received class requested

80/205 = 39.02% = percentage of non-honor roll students who did not receive class requested

72.88% of honor roll students received the preferred class as opposed to only 60.98% of non-honor roll students. Therefore, there is an advantage. 
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(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

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The particular solution y_p = Ax + B

is -4x

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Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

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(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

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