400+575+575+670+720+885+1250=5075
5075/7=725
Mean = 725
400, 575, 575, 670, 720, 885, 1250
Median = 670
725>670
C) The Mean is greater than the Median
2pt=1qt
1pt=1/2qt
therefor
multiply 2 and 3/4 by 1/2
(2 and 3/4) times 1/2=(2+3/4) times 1/2=2 times 1/2+3/4 times 1/2=2/2+3/8=1+3/8=1 and 3/8 pt
Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
1) Surface Area = 2(lw + lh + wh)
2(4*5+4*9+5*9) =202in^2
Surface Area=202in^2
Lateral Area= Perimeter of base * height
5+5=10 <--width+width
4+4=8 <---length + length
10+8=18 <--total perimeter
18 * 9=162in^2 <--multiplied the height +perimeter of base
Lateral Area=162in^2
2) Same concept as the previous one
Surface Area = 2(lw + lh + wh)
2(4*2+4*5+5*2) =76in^2
Surface Area= 76in^2
Lateral Area
Lateral Area= Perimeter of base * height
4+4=8
2+2=4
8+4=12
12 x 5=60
Lateral Area= 60in^2