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4 years ago

2+y=11 What is the answer?

Mathematics

2 answers:

Nitella [24]4 years ago

5 0

Answer:The answer has to be 9

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Step-by-step explanation: Because 2 plus 9 equals 11 and this is an addition problem

Pavel [41]4 years ago

5 0

Answer:

Step-by-step explanation:

To solve subtract 2 from both sides (subtraction property of equality)

2-2+y=11-2, then simplify

y=9

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Mary throws a plastic disc to her friend, which her friend catches six seconds after Mary throws it. The table shows the height

natta225 [31]

Unfortunately, there is no given table. However, assuming no air resistance, the projectile moves in constant acceleration in the y-axis, while constant velocity in the x-axis. If the total time of flight is 6 seconds, then at 3 seconds the reaches its maximum height. Also, there is no given initial velocity, which means any useful calculation is impossible.

8 0

3 years ago

Read 2 more answers

Solve the right triangle. Side AB is 2.9, but I don't know how to find two missing angles with three sides and a 90-degree angle

alexgriva [62]

<h3>Answer: Choice (a) in the upper left corner</h3>

Angle A = 68 degrees

Angle B = 22 degrees

Side AB = 2.9 cm

The three values are approximate

=========================================================

Explanation:

a = BC = 2.7 and b = AC = 1.1 are the two legs of the right triangle.

Use the pythagorean theorem to find the length of the hypotenuse

a^2 + b^2 = c^2

2.7^2 + 1.1^2 = c^2

8.5 = c^2

c^2 = 8.5

c = sqrt(8.5)

c = 2.91547594742266

c = 2.9

The hypotenuse is c = AB = 2.9

--------------------

We then use trig ratios to find the two missing angles.

Let's say we ignore the hypotenuse and focus on the two legs of the triangle.

With respect to reference angle A, side BC is opposite and AC is adjacent

Use the tangent ratio to get

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 2.7/1.1

tan(A) = 2.45454545454546

A = arctan(2.45454545454546)

A = 67.8336541779176

A = 68

Note: arctan is the same as inverse tangent or $\tan^{-1}$ . Make sure your calculator is in degree mode.

-------------------

Similarly,

tan(angle) = opposite/adjacent

tan(B) = AC/BC

tan(B) = 1.1/2.7

tan(B) = 0.4074074074074

B = arctan(0.4074074074074)

B = 22.166345822082

B = 22

Or you could use the value of A to get B = 90-A = 90-68 = 22. This works because A+B = 90 as we're working with a right triangle. In other words, A and B are complementary angles.

-------------------

In summary we found

A = 68

B = 22

AB = 2.9

7 0

4 years ago

What is 2.95 expressed as a fraction?<br><br><br> 59/20<br><br> 336/40<br><br> 40/118<br><br> 118/80

Verdich [7]

We rewrite the expression:
2.95 = 2 + 0.95
2.95 = 2 + 95/100
Adding fractions we have:
2 + 95/100 = (200 + 95) / (100)
2 + 95/100 = (295) / (100)
Rewriting the fraction:
(295) / (100) = 59/20
Answer:
2.95 expressed as a fraction is:
59/20

6 0

3 years ago

Read 2 more answers

A hiker is hiking in a valley. The height of the valley is h(x,y)=4x2+y2 where x and y are the east-west and north-south distanc

Ainat [17]

Answer:

A. $\frac{\partial{h}}{\partial{t}}=0$

Step-by-step explanation:

A. The problems asked for 2 ways to solve it, expanding the equation with the substitution x(t)=2 cos(t) and y(t)=4 sin(t) to differentiate it . The other way is by chain rule.

Expanding and differentiating:

We start by substituting x(t)=2 cos(t) and y(t)=4 sin(t) in h(x,y)=4x2+y2:

$h(x,y)=4x^{2}+y^{2}= 4(2cos(t))^{2}+(4sin(t))^{2}\\h(x,y)=4(4cos^{2}(t))+(16sen^{2}(t))\\h(x,y)=16cos^{2}(t)+16sen^{2}(t)=16(sen^{2}(t)+cos^{2}(t))\\h(x,y)=16$

So, in the path that the hiker chose:

$\frac{\partial{h}}{\partial{t}}=0$

Chain rule:

We start differentiating h(x,y) using chain rule as follows:

$\frac{\partial{h}}{\partial{t}}= \frac{\partial{h}}{\partial{x}}\frac{\partial{x}}{\partial{t}}+\frac{\partial{h}}{\partial{y}}\frac{\partial{y}}{\partial{t}}$

Now, it´s easy to find all these derivatives:

$\frac{\partial{h}}{\partial{x}}=8x\\\frac{\partial{x}}{\partial{t}}=-2sin(t)\\\frac{\partial{h}}{\partial{y}}=2y\\\frac{\partial{y}}{\partial{t}}=4cos(t)$