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Daniel [21]
4 years ago
10

Solve the right triangle. Side AB is 2.9, but I don't know how to find two missing angles with three sides and a 90-degree angle

. Please explain your answer.

Mathematics
1 answer:
alexgriva [62]4 years ago
7 0
<h3>Answer: Choice (a) in the upper left corner</h3>

Angle A = 68 degrees

Angle B = 22 degrees

Side AB = 2.9 cm

The three values are approximate

=========================================================

Explanation:

a = BC = 2.7 and b = AC = 1.1 are the two legs of the right triangle.

Use the pythagorean theorem to find the length of the hypotenuse

a^2 + b^2 = c^2

2.7^2 + 1.1^2 = c^2

8.5 = c^2

c^2 = 8.5

c = sqrt(8.5)

c = 2.91547594742266

c = 2.9

The hypotenuse is c = AB = 2.9

--------------------

We then use trig ratios to find the two missing angles.

Let's say we ignore the hypotenuse and focus on the two legs of the triangle.

With respect to reference angle A, side BC is opposite and AC is adjacent

Use the tangent ratio to get

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 2.7/1.1

tan(A) = 2.45454545454546

A = arctan(2.45454545454546)

A = 67.8336541779176

A = 68

Note: arctan is the same as inverse tangent or \tan^{-1}. Make sure your calculator is in degree mode.

-------------------

Similarly,

tan(angle) = opposite/adjacent

tan(B) = AC/BC

tan(B) = 1.1/2.7

tan(B) = 0.4074074074074

B = arctan(0.4074074074074)

B = 22.166345822082

B = 22

Or you could use the value of A to get B = 90-A = 90-68 = 22. This works because A+B = 90 as we're working with a right triangle. In other words, A and B are complementary angles.

-------------------

In summary we found

A = 68

B = 22

AB = 2.9

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kap26 [50]

Answer:

The answer to your question is

Part A. Archimedes grades 6 1/4 tests per day

Part B. 8 19/32 days

Part C.  6  26/29 days

Step-by-step explanation:

Part A

Total time = 6 2/5 days

Number of tests = 40 tests

Process

1.- Convert the mixed fraction to improper fraction

                 6 2/5 = (30 + 2) / 5 = 32/5

2.- Divide 40 by 32/5

                40/1  / 32/5   = (40 x 5) / (32 x 1)

                                      = 200 / 32

Simplify

                                        100 / 16 = 50/8 = 25/4

3.- Convert 25/4 to mixed fractions

                                       6      

                                4   25            

                                        1

                   25/4 = 6 1/4

Archimedes grade 6 1/4 tests per day

Part B

15 more tests

Total time = 32/5

Total tests = 40 + 15 = 55

Process

1.- Divide 55 by 32/5

                                  55 / 1  /  32 /5    = (55 x 5) / (32 x 1)

                                                             = 275 / 32

                                                             

2.- Convert 275/32 to a mixed fraction

                                                 8                                  

                                      32   275

                                             256

                                                19

Result    8 19/32 days

Part C

1.- Divide 55 by 7.25

                                         50 / 7.25     =    5000 / 725

                                                  6

                                725    5000

                                        - 4350

                                            650    

Result 6 650/750 = 6  26/29

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