Question

What are the missing values in the table representing the recursively defined geometric sequence f(x+1)=4(f(x))

Answer 1

Answer:

A=16

B=64

C=256

Step-by-step explanation:

I did the assignment

Answer 2

Answer:

Hence, the values of unknowns A,B and C are:

A=16

B=64

C=256

Step-by-step explanation:

We are given a recursive defined geometric sequence f(x+1)=4(f(x))

X       f(x)

1         4

2        A  

3        B

4        C

5      1,024

When x=1,

we have f(x)=4.

when so,

f(2)=4f(1)=4×4=16.

Hence, when x=2 f(x)=16=A.

Similarly,

f(3)=4×f(2)

f(3)=4×16=64

Hence, when x=3    f(x)=64=B.

Similarly,

f(4)=4×f(3)=4×64=256

i..e when x=4   f(x)=256=C.

similarly,

f(5)=4×f(4)=4×256=1024

when x=5   f(x)=1024

Hence, the values of unknowns A,B and C are:

A=16

B=64

C=256