What is the domain and range of h(t)=cot t

the price of an article is Marked 25% above the cost price .if it is solid the profit of Rs.500 after allowing 15% discount .wha

gavmur [86]

Answer:

Rs 8500

Step-by-step explanation:

For a cost price of c, the marked price is ...

marked = c +25%·c = 1.25c

After the 15% discount, the sale price will be ...

s = marked -15%·marked = 0.85·marked = (0.85)(1.25c) = 1.0625c

The profit will be the difference between the sale price s and the cost c:

p = s -c

500 = (1.0625c) -c = 0.0625c

Then the cost is ...

500/0.0625 = c = 8000

and the sale price is ...

s = c +p = 8000 +500 = 8500 . . . rupees

The selling price will be Rs 8500.

8 0

2 years ago

HELP! ASAP!

Novosadov [1.4K]

Step-by-step explanation:

Part A:

So the height is going to be x when you fold the sides up. So that's one part of the volume but for the width it was going to be 4 but since two corners were cut out with the length x the new width is going to be (4-2x). The same thing applies for the length which should be 8 inches but since two corners were removed with the length x it's now (8-2x)

v = x(4-2x)(8-2x)

Part B:

The volume can be graphed although there must be a domain restriction since the height, width, or length cannot be negative. So let's look at each part of the equation

so for the x in front it must be greater than 0 to make sense

for the (4-2x), the x must be less than 2 or else the width is negative.

for the (8-2x) the x must be less than 4 or else the length is negative

so the domain is going to be restricted to 0 < x < 2 so all the dimensions are greater than 0

By using a graphing calculator you can see the maximum of the given equation with the domain restrictions is 0.845 which gives a volume of 12.317

5 0

2 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago

A large container holds 8 gallons of water. It begins leaking at a constant rate. After 32 minutes, the container has 6 gallons

natta225 [31]

Answer:

I believe the answer it 0.1875

6 0

3 years ago

Read 2 more answers

Rewrite the expression 2(x + 5) using the Distributive Property.

ehidna [41]

Answer:

2x + 10

Step-by-step explanation:

To expand (using the distributive property) multiply the number outside the bracket i.e. in this case '2', with the values inside the brackets.

So multiply '2' and 'x' and '2' and 5' and add or subtract on basis of whether the second value is positive or negative.

So

2(x + 5)

= (2*x)+(2*5)

=2x+10

extention note: be careful when the symbol within the equation within the brackets is a subtraction because it implies that the second value would instead be a negative number and should be treated as such.

an example

2(x-5)

= (2*x)+(2*-5)

=2x -10

Anyhow, I hope this helped!

5 0

2 years ago