Answer:
D) would make the three-dimensional figure
As it has a maximum value the coefficient of x^2 will be negative
The vertex will be at (-8,2) so in vertex form it is
y = a(x + 8)^2 + 2
and as it passes through (-7,-1) we have:
-1 = a(-7+8)^2 + 2
-1 = a + 2 so a = -3
answer is y = -3(x + 8)^2 + 2
in standard form this is y = -3x^2 -48x - 190
This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol
Answer:
Quarters: 18.909
Nickels: 49.818
Dimes: 37.818
Somewhere around those numbers.
Step-by-step explanation:
$11.00 total in coins
Nickel = $0.05
Dime = $0.10
Quarter = $0.25
(n*0.05) + (d*0.10) + (q*0.25)
Solve the equation for q.

(n*0.05) + (d*0.10) +(
*0.25)
Simplify the expression.
9d + 2n = 440
d - n = -12
Multiply both sides of the equation by -9.
-9d + 9n = 108
9d + 2n = 440
Sum the equations vertically to eliminate at least one variable.
11n = 548

Substitute the given value of n into the equation d - n = -12


Substitute the given value of n into the equation 


Finally
d = 37.818
n = 49.818
q = 18.909
Answer:
The area of sector AOB is 75.36 unit²
Step-by-step explanation:
Consider the provided information.
Circle O with minor arc AB=60 degrees and OA =12.
We need to find the area of sector.
Area of the sector: 
Substitute
and r =12 in above formula.




Hence, the area of sector AOB is 75.36 unit²
Answer:
........??
Step-by-step explanation:
huh whattt