90,000,000 divided by 3,000
2 answers:
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Answer:
Step-by-step explanation:
Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12
Number of Blue Marbles{1,2,3,4,5,6},n(B)=6
Total Number of Marbles, n(S)=6+12=18
(a)Probability that the Marble is Red
(b)Probability that the marble is odd-numbered.
Number of Odd-Numbered Balls, n(O)=9
(c)Probability that the marble is red or odd-numbered.
n(Red)=12
n(Odd Numbered marbles)=9
n(Red and Odd Numbered Marbles)=6
(d)Probability that the marble is blue or even-numbered.
n(Blue)=6
n(Even Numbered marbles)=9
n(Blue and Even Numbered Marbles)=3
Answer:
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = 7
The Toy company sells Shaq Size hoops = 3
Step-by-step explanation:
Given - The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size. A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together. The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes. The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
To find - What is the maximum profit they can make given the constraints above?
Proof -
Let us assume that,
The Toy company sells Jordan Size hoops = x
The Toy company sells Shaq Size hoops = y
Now,
Given that, A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together.
⇒x + y ≤ 10
Now,
Given that, The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes.
⇒ x ≥ 2
y ≥ 3
Now,
Given that,
The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
So,
The objective function becomes
Z = 1350x + 1200 y
So,
The Linear Programming Problem (LPP) becomes
Maximize Z = 1350x + 1200 y
Subject to
x + y ≤ 10
x ≥ 2
y ≥ 3
x, y ≥ 0
We will Solve the LPP by Graphical method.
The graph is as follows :
The points on the Boundary are -
A(2, 8)
B(2, 3)
C(7, 3)
So,
Points (x,y) Objective function value ( Z = 1350x + 1200y)
B(2,3) 1350(2) + 1200(3) = 6300
C(7,3) 1350(7) + 1200(3) = 13050
A(2,8) 1350(2) + 1200(8) = 12300
So,
Maximum value = 13050 at point C(7,3)
∴ we get
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = x = 7
The Toy company sells Shaq Size hoops = y = 3
