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gavmur [86]
3 years ago
8

7x/5+5/2=x/10+1/5 SHOW WORK!!! PLEASE HELP!!!! WILL MARK BRAINLIEST

Mathematics
1 answer:
Anettt [7]3 years ago
3 0

Answer:

- 23/13

Step-by-step explanation:

1. Subtract 5/2 from both sides of the equation.

2. Simplify

7/5 = /10 − 23/10

3. Multiply all terms by the same value to eliminate fraction denominators.

7/5 = /10 − 23/10          2 ⋅ 5 ⋅ 7/5 = 2 ⋅ 5( /10 − 23/10)

4. Simplify

14 = − 23

5. Subtract from both sides of the equation.

14 = − 23                              14 − = − 23 −

6. Simplify

13 = − 23

7. Divide both sides of the equation by the same term.

13<em>x </em>= −23                          13x/13 = -23/13

8. Simplify

= −23/13

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Point R is on line segment QS. Given RS= 5 and QS<br> 5 and QS = 16, determine the length<br> QR.
amid [387]

The value of QR is 11

<h3>How to determine the length of QR?</h3>

The given parameters are:

RS = 5

QS = 16

Because R is on QS, then we have:

QS = QR + RS

This gives

16 = 5 + QR

Evaluate

QR = 11

Hence, the value of QR is 11


Read more about lengths at:

brainly.com/question/17297081

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8 0
2 years ago
Can somebody help me asap I need this finished
Alexus [3.1K]

Answer:

A) y=5x-3

Step-by-step explanation:

8 0
3 years ago
A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of
koban [17]
Lateral Area = PI * radius * slant height
Lateral Area = 3.14159 * 1.5 * 5
Lateral Area = <span> <span> <span> 23.561925 </span> </span> </span>

The answer is 24 square inches.

Source:
http://www.1728.org/volcone.htm


3 0
3 years ago
the common ratio in geometric series is 0.5 and the first term is 256. what is the sum of the first 6 terms in the series?
melisa1 [442]

Answer:

501.76

Step-by-step explanation:

common ratio r = 0.5

first term a = 256

sum of G.p = Sn= a( r^n -1)/r-1

sum of the first 6 terms =

S6 = 256( 0.5^6 - 1)/ 0.5 - 1

= 256( 0.0156 - 1)/-0.5

= 256( -0.98)/-0.5

= - 250.88/-0.5

S6 = 501.76

7 0
3 years ago
Is d = 8 a solution to the inequality below?<br><br> 49<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" a
seraphim [82]
Answer:

No

Step-by-step explanation:

49 ≥ 10d

49 ≥ 10(8)

49 ≥ 80

49 has to be greater than or equal to 80

d = 8 isn’t a solution
8 0
3 years ago
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