About how much of the cell mass is watet

Which structure is found in all eukaryotic cells

Marizza181 [45]

Answer:

unlike prokaryotic cells, eukaryotic cells have: a membrane-bound nucleus. numerous membrane-bound organelles (including the endoplasmic reticulum, Golgi apparatus, chloroplasts, and mitochondria) several rod-shaped chromosomes.

Explanation:

brainliest ??

6 0

3 years ago

What is the action of nature producing new organisms over time known as?

Korolek [52]

I am so sorry but I don’t know the answer, I just needed the points to ask a question myself

3 0

3 years ago

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pThe probability of having an offspring with both the dominant phenotypes for both genes is equal to the product of the individu

Elena-2011 [213]

The product probability rule states P(A∩B) = P(A) x P(B). In the exposed example, the probability of having a dominant phenotype is 9/16.

<h3>What is the product probability rule?</h3>

The product probability rule allows us to calculate the probability of occurrence of event A and event B at the same time.

It is about a joint probability of two or more events that might happen simultaneously, not excluding each other.

This rule is based on the dependence or independence of the events. If two events A and B are independent of each other, the occurrence of one of them does not affect the occurrence of the other one.

For independent events, the rule establishes that, given two different events A and B, the probability of occurrence of both together is

P(A∩B) = P(A) x P(B)

The probability of inheriting one of the alleles from each parent is 0.5 (beacause each parent has two alleles).

According to this, the probability of having a dominant phenotype for both traits depends on the paretal genotypes.

For instance, let us analyze the cross between two dihybrid individuals AaBb x AaBb.

Assuming the involved genes code for different traits and both are independent genes, for easier calculations, we can perform crosses that involve each of the genes separately -events-, and then multiply de results according to the genotype and phenotype we are interested in (A-B-)

Gene A

Parentals) Aa x Aa

Gametes) A a A a

Punnett square) A(1/2) a(1/2)

A(1/2) AA(1/4) Aa(1/4)

a(1/2) Aa(1/4) aa(1/4)

F1) Genotype

1/4 AA ⇒ 1/2A x 1/2A

2/4 = 1/2 Aa ⇒ (1/2A x 1/2a) + (1/2A x 1/2a)

1/4 aa ⇒ 1/2a x 1/2a

Phenotype

3/4 A- ⇒ 1/4AA + 2/4Aa

1/2 aa

Gene B

Parentals) Bb x Bb

Gametes) B b B b

Punnett square) B b

B BB Bb

b Bb bb

F1 Genotype

1/4 BB ⇒ 1/2B x 1/2B

2/4 = 1/2 Bb ⇒ (1/2B x 1/2b) + (1/2B x 1/2b)

1/4 bb ⇒ 1/2b x 1/2b

Phenotype

3/4 B- ⇒ 1/4 BB + 2/4 Bb

1/2 bb

The probability of having a dominant genotype and phenotype for both traits is,

Genotpe AABB ⇒ 1/4 AA x 1/4 BB = 1/16 AABB

Phenotype A-B- ⇒ 3/4 A- x 3/4 B- = 9/16 A-B-

You can learn more about the product probability rule in crosses at

brainly.com/question/13049972

brainly.com/question/14933381

4 0

3 years ago

You are at the store with your friend's family and they are looking to buy a new refrigerator for their home. There are two opti

maksim [4K]

Answer:

It will take 83 days to recover the extra cost

Explanation:

To determine the length of time it will take to recover the extra cost, it will be logical that we compare the $200 extra cost to the total savings in running cost made for a year and covert this into days

The total savings in running cost is the cost savings per hour multiplied by the number of hours in a year.

The calculations are set below:

Savings in running cost per hour = $0.1

Total savings in a year = 365 days × $0.1 × 24 = $876

Extra cost of Energy Star refrigerator = $200

If total savings for a year is $876 , then equivalent length of time to save $200 would be

Length of time = 200/876 × 365 days = 83 days

It will take 83 days to recover the extra cost

Explanation:

3 0

2 years ago

If mice from the F1 generation are crossed, their offspring are the .

Anton [14]

Answer: The answer is the F2 Generation!

Explanation:

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5 0

3 years ago