P( both allergic) = 0.17*0.17 = 0.0289
P(at least one is allergic) = 1 - P(neither are allergic) = 1 - 0.83^2 = 0.311
Answer:
Step-by-step explanation:
![\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7Bx%2B7%7D%7Bx%5E2%2B4x-21%7D%20%5Cdiv%20%5Cfrac%7Bx%2B5%7D%7Bx%5E2%2B8x%2B15%7D%20%5C%5C%5C%5CApply%20%5C%20mid-term%20%5C%20break%5C%5C%5C%5C%3D%20%5Cfrac%7Bx%2B7%7D%7Bx%5E2%20%2B7x-3x-21%7D%20%5Cdiv%20%5Cfrac%7Bx%2B5%7D%7Bx%5E2%20%2B3x%2B5x%2B15%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7Bx%2B7%7D%7Bx%28x%2B7%29-3%28x%2B7%29%7D%20%5Cdiv%20%5Cfrac%7Bx%2B5%7D%7Bx%28x%2B3%29%2B5%28x%2B3%29%7D%20%5C%5C%5C%5CTaking%20%5C%20%28x%2B3%29%20%5C%20and%20%5C%20%28x%2B7%29%20%5C%20common%5C%5C%5C%5C%3D%20%5Cfrac%7Bx%2B7%7D%7B%28x-3%29%28x%2B7%29%7D%20%5Cdiv%20%5Cfrac%7Bx%2B5%7D%7B%28x%2B3%29%28x%2B5%29%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7Bx-3%7D%20%5Cdiv%20%5Cfrac%7B1%7D%7Bx%2B3%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7Bx-3%7D%20%2A%20%28x%2B3%29%5C%5C%5C%5C%3D%20%5Cfrac%7Bx%2B3%7D%7Bx-3%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
13
Step-by-step explanation:
All the lengths in triangle ADE are twice those in similar triangle ABC. So ...
x-1 = 2(6)
x = 13
Answer:
the answer b
Step-by-step explanation:
[surface area]=[area of 4 triangles sides]+[area of square base]
[area of square base]=24*24--------> 576 cm²
[area of one triangles side]
l=slant height
l²=16²+12²-------> l²=400-----------> l=20 cm
[area of one triangles side]=24*20/2--------> 240 cm²
[area of 4 triangles sides]=4*240----------> 960 cm²
[surface area]=[960]+[576]--------> 1536 cm²
