<h3>
Answer: 3x^3 + 11x^2 - 5x - 25</h3>
Work Shown:
yz = y(x^2+2x-5)
yz = y(x^2) + y(2x) + y(-5)
yz = x^2( y ) + 2x( y ) - 5( y )
yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )
yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5
yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25
yz = 3x^3 + 11x^2 - 5x - 25
Answer: (7.27%, 7.55%)
Step-by-step explanation:
As per given , we have
Sample size : n= 392
Sample mean : 

Critical two-tailed z-value for 95% confidence = 
Required confidence interval would be :

Hence, the required 95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies : (7.27%, 7.55%)
I don’t know
Igditditditd
They put 138 into groups of 6, so divide 138 by 6.
138/6
23 craft kits.
Hope this helps! :D
Answer: It's false.
I believe you would do (5-3) first.