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ipn [44]
3 years ago
6

List the gcc command-line options for each of the following: Generate a .o file rather than an executable. Generate a .s (assemb

ly code) file rather than an executable. Enable the highest level of optimization. Enable optimizations that do not make debugging more difficult. Include debugging information in the executable file.
Computers and Technology
1 answer:
natka813 [3]3 years ago
4 0

Answer:

see attached file.

Explanation:

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kolbaska11 [484]
The first one is d the second one is true the third one is false
3 0
3 years ago
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
3 years ago
Write a program that reads three whole numbers and displays the average of the three number. Sample Run #: java Average3 Interac
Maksim231197 [3]

Answer:

The program to this question as follows:

Program:

import java.util.*; //import package

class Average //defining class Average

{

public static void main(String[] args) //defining main method

{

int a1,b2,c3;//defining integer variable

float avg; //defining float variable

Scanner obz=new Scanner(System.in); //creating scanner class object

System.out.print("input first number: "); //print message

a1=obz.nextInt(); //input value by user

System.out.print("input second number: "); //print message

b2=obz.nextInt(); //input value by user

System.out.print("input third number: "); //print message

c3=obz.nextInt(); //input value by user

avg=a1+b2+c3/3; //calculating average

System.out.print("The average of "+a1+","+b2+",and "+ c3+"="+ avg);//print value    

}

}

Output:

input first number: 8

input second number: 10

input third number: 18

The average of 8,10,and 18=24.0

Explanation:

In the above code, a class "Average" is defined inside this class the main function is declared in this method three integer variable "a1, b2, and a3" is declared, which input the value from the user side. in this method, a float variable avg is defined that calculates its average value.

  • In the next step, a scanner class object is created, that uses the above integer variable values.  
  • In the "avg" variable add all integer variables then divide its value by 3. At the print, method is used that prints avg variable value.
4 0
3 years ago
Assume that the int variables i and j have been declared, and that n has been declared and initialized.
timama [110]

Answer:

public class num6 {

   public static void main(String[] args) {

       int n = 4;

       for(int i = 1; i <= n; ++i) {

           for(int j = 1; j <= i; ++j) {

               System.out.print("* ");

           }

           System.out.println();

       }

   }

}

Explanation:

This solution is implemented in Java

Two for loops are required for this (an inner nd outer for loop).

The innner and outer for loops can be seen as implementing rows and columns (so on the first 'row' i=1, so a single star is printed, on the second row, i =2, two stars are printed and so on, all on seperate lines)

8 0
3 years ago
Katrina studied hard for a biology test about the anatomy of a frog, but she did poorly and is using the "glows and grows” strat
melomori [17]

Answer:

how the frog grows through its life

Explanation:

7 0
3 years ago
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