Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
A good algorithm should have these three components: C. steps, order, and outcomes.
<h3>What is an algorithm?</h3>
An algorithm simply refers to a standard formula which is made up of a set of finite steps and instructions that are executed on a computer system, in order to enable a software solve a particular problem under appropriate conditions.
In Computer technology, there are three (3) components that a good algorithm should have these include the following:
Read more on algorithm here: brainly.com/question/24793921
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Answer:
The program written in Python is as follows:
<em>See Explanation section for line by line explanation</em>
for n in range(100,1000):
isum = 0
for d in range(1,n):
if n%d == 0:
isum += d
if isum == n * 2:
print(n)
Explanation:
The program only considers 3 digit numbers. hence the range of n is from 100 to 999
for n in range(100,1000):
This line initializes sum to 0
isum = 0
This line is an iteration that stands as the divisor
for d in range(1,n):
This line checks if a number, d can evenly divide n
if n%d == 0:
If yes, the sum is updated
isum += d
This line checks if the current number n is a double-perfect number
if isum == n * 2:
If yes, n is printed
print(n)
<em>When the program is run, the displayed output is 120 and 672</em>
