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natima [27]
4 years ago
12

What is the solution to the linear equation below? 6 + y = 37

Mathematics
2 answers:
slavikrds [6]4 years ago
3 0
Y=31----------------------------------------------------------------
wolverine [178]4 years ago
3 0
The answer choices (if you are using PLATO for this question) are:
A. 6
B.31
C.41
D.222

The answer to this question should be B. 31, because when you subtract 6 from 37, you get 31. To check, plug the 31 into the equation. 6+31=37!

I hope this helps you! Have a great day!
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100% is 320votes. What is 70%? 70%* 320 / 100 = 224 was the votes that the winning candidate receive
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If the roots (x-2)^2=k are equal find the value of k
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Answer:

\% Below\ 50 = 88 \%

\% 43\ or\ more = 17 \%

Step-by-step explanation:

Given

Total = 200

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10

Frequency = 176

The percentage is then calculated as:

\% Below\ 50 = \frac{Frequency}{Total} * 100\%

\% Below\ 50 = \frac{176}{200} * 100\%

\% Below\ 50 = \frac{176* 100}{200} \%

\% Below\ 50 = \frac{176* 1}{2} \%

\% Below\ 50 = \frac{176}{2} \%

\% Below\ 50 = 88 \%

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

Frequency = 10 + 7 + 5+12

Frequency = 34

The percentage is then calculated as:

\% 43\ or\ more = \frac{Frequency}{Total} * 100\%

\% 43\ or\ more = \frac{34}{200} * 100\%

\% 43\ or\ more = \frac{34* 100}{200} \%

\% 43\ or\ more = \frac{34* 1}{2} \%

\% 43\ or\ more = \frac{34}{2} \%

\% 43\ or\ more = 17 \%

7 0
3 years ago
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