Answer:
0.078
Step-by-step explanation:
Margin of error = z√(p(1-p)/n)
Given
p-hat = 0.43
n = 270
z at 99% confidence interval = 2.576
Substitute
MOE = 2.576√0.43(1-0.43)/270
MOE = 2.576√0.43*0.57/270
MOE = 2.576√0.2451/270
MOE = 2.576*0.030129
MOE = 0.078
Hence the margin og error is 0.078
If 7 people paid $3 per ride and road 5 times, it would be $21 dollars. You could do it 3×5=15+7=21
<em>a = 30°</em>
<em>b = 70°</em>
<em>c = 80°</em>
- Step-by-step explanation:
<em>Hi there ! </em>
<em />
<em>a ; b ; c = angles</em>
<em>a + b + c = 180°</em>
<em>b + c = 5a</em>
<em><u>replace (b + c)</u></em>
<em>a + (b + c) = 180</em>
<em>a + 5a = 180</em>
<em>6a = 180</em>
<em>a = 30°</em>
<em />
<em>b + c = 180 - a</em>
<em>b + c = 150</em>
<em>c = b + 10</em>
<em><u>replace c</u></em>
<em>b + (b + 10) = 150</em>
<em>2b = 150 - 10</em>
<em>2b = 140</em>
<em>b = 70°</em>
<em>c = b + 10</em>
<em>c = 80°</em>
<em>Good luck !</em>
Answer: 126.48x+109.56 would be the largest possible perimeter if the area is 1000x + 750.
Step-by-step explanation: Not 100% certain of this answer.
find square root...
31.62x+27.39
that would give us 4 sides and since perimeter of rectangle is 2l+2w...
4(31.62x+27.39)=
126.48x+109.56 would be the largest possible perimeter if the area is 1000x + 750.
Given:
24,000 books
Between 3 and 4 books will have a printing error in every
3000 printed books
Find: in the
24000 books, the total number of books that will have a printing error
Solution:
Based from the given,
we need to know how many sets of 3000 we
have in the 24000
books so:
24000 / 3000 = 8
Now, in each set of
3000 we have between 3 and 4 errors and we have 8 sets of 3000 books:
minimum errors 3 * 8 =
24
maximum errors 4 * 8 =
32
Therefore, at this
rate, the number of books that will have a printing error in the
24000
<span>will be between 24 and
32 or 24 < E < 32.</span>
