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ra1l [238]
3 years ago
6

In the late 1980s, however, unusually warm weather caused many of the pools that the toads used as breeding areas to dry up. By

2004, the golden toad was listed as extinct. This example demonstrates how A. extinction can be related to invasion by non-native species competing for resources. B. extinction can be related to a failure to adapt to changes in the environment. C. extinction is caused by bacteria, fungi, and other infectious agents. D. extinction is directly related to human impact.
Biology
2 answers:
sweet [91]3 years ago
5 0

Answer:

Option B, extinction can be related to a failure to adapt to changes in the environment.

Explanation:

Here,

The toads species became extinct as the pools used by them for breeding dried up. If these toad would have adapted themselves to mate even in dry condition or without water they would have survived.

Drying up of pool is a natural event resulting into change in native environment.

Option A is not correct  as in this scenario as there were no native species other than the toads which were consuming the resource

Also option C, is not correct as in this scenario the extinction was not related to infection caused by any microorganism like bacteria etc.

Option D is also incorrect as there was no involvement of humans,  which had  led to the drying up of pool.

Thus, only option B is a possible answer to this question

Sav [38]3 years ago
4 0

the answer is B.extinction can be related to a failure to adapt to changes in the environment.

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3 years ago
In a population of 200, 86 individuals express the recessive phenotype. What percent of the population would you predict would b
Nitella [24]

Answer:

The correct option is;

D. 45%

Explanation:

From the Hardy- Weinberg law, we have;

p² + 2·p·q + q² = 1

p + q = 1

Where:

p = Dom inant allele frequency in the population

q = Recessive allele frequency in the population

p² = The percentage of individuals in the population that are hom ozygous dominant

q² = The percentage of individuals in the population that are homo zygous recessive

2×p×q = The percentage of hete rozyous individuals in the population

The number of individuals that express the recessive phenotype = 86

The number of individuals in the population = 200

The percentage of  individuals that express the recessive phenotype, q² = 86/200 = 0.43

Therefore;

q = √0.43 = 0.656

p + q = 1

p = 1 - q = 1 - 0.656= 0.344

∴ The frequency of  individuals that express the do minant phe notype, p = 0.344

The percentage of heterozyous individuals in the population = 2×p×q × 100 = 2 × 0.656 × 0.344 × 100 = 45.15% ≈ 45%

3 0
3 years ago
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