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3 years ago

13

The speed of a car is increased at a constant rate. If the speed is increased by 54m/s over a 6 second period what is the accele

ration

1 answer:

Anna35 [415]3 years ago

3 0

Answer:

9ms^-2

Step-by-step explanation:

a = dV/dt

a = 54ms^-1/6s

a = 9ms^-2

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Journal entry

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2 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

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Answer with explanation:

The given differential equation is

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Let, y'=z

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Substituting the value of , y, y' and y" in equation (1)

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This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

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3 years ago

Rob is buying some green apples to make some fresh apple juice. The price of the green apples is G and Rob has a coupon for 10%

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C) g-0.1g
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2 years ago

Read 2 more answers

maksim [4K]

<u>Part A</u>

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The x-coordinate of the vertex is $x=-\frac{-7}{2(4)}=\frac{7}{8}$

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Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

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2 years ago

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Answer:

it is .25 :)

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3 years ago