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2 years ago

Whats the value of 4 in 46,395 and the value of 4 in 14,906

Mathematics

1 answer:

bogdanovich [222]2 years ago

6 0

The 4 in 46,395 is 10 times the 4 in 14,906.

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peter and his four brothers combined all of their money to buy a video game. if 20%of the total money is peters and $12.00 of th

Tamiku [17]

Answer:

60$ (b)

Step-by-step explanation:

we know that 20% of the total is peters - and peter has 12 dollars. We know that 20% 5 times gets us to 100%. So we multiply 12 by 5 to get a total answer of 60$

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3 years ago

Choose the slope-intercept form of 3x + 2y = 5

lianna [129]

Answer:

Step-by-step explanation:

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3 years ago

Solve for :<br>(x+3)/2=6

Marianna [84]

Answer:

x=9

Step-by-step explanation:

(x+3)/2=6

Multiply each side by 2

2*(x+3)/2=6*2

x+3 = 12

Subtract 3 from each side

x+3-3 = 12-3

x = 9

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2 years ago

Suppose I am playing a sport that does not allow me to end a match in a tie (AKA I have to either win or lose). If my probabil

Leviafan [203]

Answer: The required probability is 0.3456.

Step-by-step explanation:

Since we have given that

Probability of winning at any given time = 0.6

Probability of losing at any given time = 1-0.6 = 0.4

Number of total matches = 5

Number of won matches = 3

So, using "Binomial distribution", we get that

$P(X=3)=^5C_3(0.6)^3(0.4)^2\\\\P(X=3)=0.3456$

Hence, the required probability is 0.3456.

6 0

3 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

3 years ago