Answer:
15
Step-by-step explanation:
5:22=15:66, simply multiply 3 in the right hand side
Answer:
We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Step-by-step explanation:
We are given that in a group of randomly selected adults, 160 identified themselves as executives.
n = 160
Also we are given that 42 of executives preferred trucks.
So the proportion of executives who prefer trucks is given by
p = 42/160
p = 0.2625
We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.
We can use normal distribution for this problem if the following conditions are satisfied.
n×p ≥ 10
160×0.2625 ≥ 10
42 ≥ 10 (satisfied)
n×(1 - p) ≥ 10
160×(1 - 0.2625) ≥ 10
118 ≥ 10 (satisfied)
The required confidence interval is given by
Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.
Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96
Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Answer:
x=58, m<DCB=56°
Step-by-step explanation:
Ok the sum of those two angles should equal 180 degrees so,
2x+8+x-2=180
solve the equation
3x+6=180
3x=174
x= 58
M<DCB=x-2--> 58-2=56
(-7,1) is a solution to the inequality y<0.5x+9
-- Reflecting across the x-axis makes all the x-coordinates the negative of
what they were before the reflection. The y-coordinates don't change.
-- Translating 2 units up makes all the y-coordinates 2 greater than
they were before the translation. The x-coordinates don't change.
You didn't give us a list of new coordinates, so there's nothing
to match with.