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tankabanditka [31]
3 years ago
7

1. In the morning, the temperature

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

21.4

Step-by-step explanation:

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Which relationship describes angles 1 and 2?
In-s [12.5K]

Answer:

Supplementary Angles

Adjacent Angles

Step-by-step explanation:

Angles 1 and 2 share a vertex and form a straight line. These angles are called supplementary angles. They add to 180 degrees and form a straight line. They are adjacent as well because they share a vertex and side.

3 0
3 years ago
Can someone explain the steps for how do solve this?! I can’t get it right
Ulleksa [173]

Answer:

x = 50

m∠D = 150°

m∠F = 30°

Step-by-step explanation:

  • supplementary angles are two angles whose sum is 180°

∠D + ∠F = 180°

3x + x - 20 = 180

3x + x = 180 + 20

4x = 200

x = 200/4

x = 50

D = 3*50 = 150

∠D = 150°

F = 50 - 20 = 30

∠F = 30°

6 0
3 years ago
A new basketball is 40% off of its original price and is now selling for $36.00. What was the original price of the basketball b
VikaD [51]
Multiply 40% and 36.00 than add what you get to 36.
6 0
3 years ago
Which pairs make the equation x-9y=12 true
Serggg [28]

Answer:

(12,0), (3, -1) (0,-4/3)

Step-by-step explanation:

To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.

6 0
3 years ago
A fair die is cast four times. Calculate
svetlana [45]

Step-by-step explanation:

<h2><em><u>You can solve this using the binomial probability formula.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows:</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)</u></em></h2>
8 0
3 years ago
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