Answer:
Smaller Figure 3
Larger Figure 5
Scale factor = 15/25 = 3/5
We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
Answer:
The 90 % confidence interval for the mean population is (11.176 ; 20.824 )
Rounding to at least two decimal places would give 11.18 , 20.83
Step-by-step explanation:
Mean = x`= 16 miles per hour
standard deviation =s= 4.1 miles per hour
n= 4
= 4.1/√4= 4.1/2= 2.05
1-α= 0.9
degrees of freedom =n-1= df= 3
∈ ( estimator t with 90 % and df= 3 from t - table ) 2.353
Using Students' t - test
x`±∈ * 
Putting values
16 ± 2.353 * 2.05
= 16 + 4.82365
20.824 ; 11.176
The 90 % confidence interval for the mean population is (11.176 ; 20.824 )
Rounding to at least two decimal places would give 11.18 , 20.83
(-2, 4)
Hope this helps! If not I, truly sorry