Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.
Do this by changing the equations so that the coefficients of either x or y add up to 0.
Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0
Multiply 2nd equation by -1.
6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8
Solve for x
4x = 8
x = 8/4 = 2
Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1
Therefore solution is (2,-1)
Given:
To find the vertical and horizontal asymptotes:
The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.
But, here there is no such point.
Thus, the function f(x) doesn't have a vertical asymptote.
The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.
Thus, y = 0 is the horizontal asymptote for the given function.
Width = w
Length = 5w
Given,
Perimeter = 276 ft
5w * w = 276
w² = 55.2
--- w = 7.429670248402684 ≈ 7.43 ft
--- l = 5w = 5*7.43 = <span>37.14835124201342 </span>≈ 37.15 ft
Distinct prime factors are factors that can not be reduced any further.... Such factors are like 3,5, and 7.
Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:
a)
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082
b)
The area to the left of z=3.00 is 0.9987
c) The z-value of 1200 is 0
The area to the left of 0 is 0.5
The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is
d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e)
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1