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3 years ago

T-4t^2+2t^3 what is the degree of the polynomial

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

Answer:

Step-by-step explanation:

three

kirza4 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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NOT GRADED. FIND THE MEASURE OF THE INDICATED ANGLE IN EACH TRIANGLE.

Setler [38]

Answer:

The angle in the box is always 50 and that other acute angle is 46

Hope this helps

Step-by-step explanation:

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3 years ago

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What is (-i)^5? A. 1 B. i C. -1 D. -i

jenyasd209 [6]

Answer:

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3 years ago

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What is the awnser to this question because I don't understand

Virty [35]

Pemdas 1. parentheses: everything is already in parentheses. so next is exponents. 10×-2 is -20. and 10×6 is 60. so 4×-20 is the next step. it equals -80. and then 3×60 is 180. lastly,add -80 and 180 together. the answer should be 100 if i did that correctly.

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3 years ago

Partition a number line from 0 to 1 into sixth decompose 2/6 into 4 equal lengths.

Anon25 [30]

When we partition a number line from 0 to 1 into six, each segment has a length of 1/6 and the segments are:
1/6. 2/6. 3/6, 4/6, 5/6 , 6/6

Breaking 2/6 into 4 equal parts, we get each part equal to 1/12

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3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

3 years ago