Let S = his average speed.
Let D = distance traveled one way
Time = distance / speed
Set up an equation:
d/6 + d/12 = 2d/S
Multiply the equation by 12s:
12s(d/6) + 12s(d/12) = 12s(2d/s)
Simplify to get:
2sd + sd = 24d
Combine like terms:
3sd = 24d
Divide both sides by d:
3s = 24
Divide both sides by 3:
s = 24/3
s = 8
 His average speed was 8 mph.
 
        
             
        
        
        
Answer:
 7 hours and 9 minutes 
Step-by-step explanation:
4 hours and 33 minutes is 273 minutes 
7 m/s —> 273 minutes
11 m/s —> M
Criss cross to get M
11x273= 7M
3003=7M
M=429 minutes
==> 429 minutes is 7 hours and 9 minutes 
 
        
             
        
        
        
Answer:
The distance of ship B from the Harbor is 32.26 miles
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.
I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

 .... flip both fractions.
 .... flip both fractions.
 .... multiply both sides by 22
 .... multiply both sides by 22


So the distance of ship B from the Harbor is 32.26 miles
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
 
        
             
        
        
        
Answer:
45 or positive 45 
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
A square
Step-by-step explanation: