Let S = his average speed.
Let D = distance traveled one way
Time = distance / speed
Set up an equation:
d/6 + d/12 = 2d/S
Multiply the equation by 12s:
12s(d/6) + 12s(d/12) = 12s(2d/s)
Simplify to get:
2sd + sd = 24d
Combine like terms:
3sd = 24d
Divide both sides by d:
3s = 24
Divide both sides by 3:
s = 24/3
s = 8
His average speed was 8 mph.
Answer:
7 hours and 9 minutes
Step-by-step explanation:
4 hours and 33 minutes is 273 minutes
7 m/s —> 273 minutes
11 m/s —> M
Criss cross to get M
11x273= 7M
3003=7M
M=429 minutes
==> 429 minutes is 7 hours and 9 minutes
Answer:
The distance of ship B from the Harbor is 32.26 miles
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.
I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

.... flip both fractions.
.... multiply both sides by 22


So the distance of ship B from the Harbor is 32.26 miles
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
45 or positive 45
Step-by-step explanation:
Answer:
A square
Step-by-step explanation: