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const2013 [10]
3 years ago
5

0.007 0.07 0.7 7 what’s next

Mathematics
1 answer:
Reika [66]3 years ago
3 0

Answer:

77

Step-by-step explanation:

Because your slowly moving up a place

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Y+3 1/2=6 help pleaseee
Verdich [7]
3 1/2 = 7/2
so y+7/2 = 6
y=6-7/2 = 12-7 / 2 = 5/2 = 2 1/2
8 0
3 years ago
Hey guys can you please help me?? Thank you!
yarga [219]
The answer is 5 :)
44+51=95
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answer: 5
3 0
3 years ago
Read 2 more answers
A cylinder has a base area of 64π m2. Its height is equal to twice the radius. Identify the volume of the cylinder to the neares
Maurinko [17]

Answer:

3215 .36 m³ is the required volume.

Step-by-step explanation:

Base area of Cylinder = 64π m²

Height of cylinder is equal to twice the radius .

As we know that ,

★Base Area of Cylinder = πr²

where,

π is taken as 22/7 or 3.14

r is the radius of cylinder

Substitute the value we get

↝ 64 π = πr²

↝ 64 = r²

↝ √64 = r

↝ 8 = r

↝ r = 8 m

Now, it is given that height is equal to twice of radius

Therefore ,

height = 2r = 2×8 = 16 m

★Volume of Cylinder = πr²h

substitute the value we get

↝ volume of Cylinder = 3.14 × 8² × 16

↝volume of Cylinder = 3.14 × 64 × 16

↝volume of Cylinder = 3215 .36 m²

Hence, the required volume of cylinder is 3215 .36 m³.

6 0
3 years ago
Which of the following statements are true based on the diagram?
WINSTONCH [101]
Its true yo 1234567891011121314
5 0
4 years ago
A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 686 cubic feet. The concrete f
kobusy [5.1K]

Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

                                                    =x²

The volume of the box is = area of the base × height

                                          =x²h

According to the problem,

x²h=686

\Rightarrow h=\frac{686}{x^2} .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50  per square foot.

The material cost for sides =$(3.50× 4xh )

                                             =$14xh

Total cost =$(5x²+9x²+14xh)

                =$(14x²+14 xh)

Let

C = 14x²+14 xh

Putting h=\frac{686}{x^2}

C=14x^2+14 x.\frac{686}{x^2}

\Rightarrow C=14x^2+\frac{9604}{x}

Differentiating with respect to x

C'= 28x-\frac{9604}{x^2}

Again differentiating with respect to x

C''= 28+\frac{19208}{x^2}

To find the dimension set C'=0

28x-\frac{9604}{x^2}=0

\Rightarrow 28x=\frac{9604}{x^2}

\Rightarrow x^3=\frac{9604}{28}

\Rightarrow x=7

Now,

C''|_{x=7}= 28+\frac{19208}{7^2}>0

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

The height of the box is  h=\frac{686}{x^2}

                                            =\frac{686}{7^2}

                                            =14 foot

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

The cost of the material is =14x^2+\frac{9604}{x}

                                              =14(7)^2+\frac{9604}{7}

                                             =$2,058

6 0
4 years ago
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