21.6 units
Calculate the length of the 2 inclined sides using the distance formula
d = √(x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 3, 3 ) and (x₂, y₂ ) = (3, 4 )
d = √(3 + 3 )² + (4 - 3)² = √(36 + 1 ) = √37
repeat for (x₁, y₁ ) = (- 3, 3 ) and (x₂, y₂ ) = (3, - 3 )
d = √(3 + 3 )² + (- 3 - 3 )² = √(36 + 36 ) = √72
the vertical side has a length of 7 units
perimeter = √37 + √72 + 7 = 21.6 ( nearest tenth of a unit )
Answer: 1:52 PM
Step-by-step explanation:
PAULA: 2:14PM FINISHED THE RACE
BEATRICE: FINISHED 22 MINUTES EARLIER THEN PAULA
YOU TAKE 2:14PM AND SUBTRACT THE 22 MINS BEATRICE RAN TO GET YOU ANSWER.
SO 2:14 -14 MINS=2:00PM 14+8=22 (THE MINS BETRICE FINISHED)
2:00-8 MINS ( REMAINING FROM THE 22 ) THEN 2:00-8 MINS =1:52
ANSWER:1:52PM
If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x.
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair.
Answer:
i think its either the first or second one but imma go w the first
Step-by-step explanation:
Y= 2x-3 i think, but i may be wrong
