Midpoint (2,5) (-1,9)

Use the quadratic formula to solve the quadratic equation x2 − 8x − 4 = 0.

mixas84 [53]

Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu

4 0

3 years ago

I would love if someone would help me

mart [117]

I’m hoping this helps (but hopefully now you can give the brainliest to the person above)
I’m not very familiar with the square roots method but I believe you try and isolate the term that is squared.

4 0

3 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

4 years ago

!!!!Please help!!! I am dying!!

stellarik [79]

Answer:

Therefore (x,y)=(3,7)

Step-by-step explanation:

put the second equation into the first

x+4=3x-2

x-3x=-2-4

-2x=-6

x=3

plug x=3 into the second equation

y=3+4=7

6 0

1 year ago

The triangles below are similar. Triangle Y X Z. Side Y X is 6 centimeters, X Z is 7 centimeters, and Z Y is 3 centimeters. Tria

zavuch27 [327]

Answer:

(c) Triangle Z Y X is similar to triangle C B A

Step-by-step explanation:

Triangles are similar when corresponding sides have the same ratio. Corresponding sides will have corresponding end point vertices. The similarity statement lists corresponding vertices in the same order.

__

<h3>corresponding sides</h3>

The side lengths, smallest to largest, for the two triangles are ...

3 cm -- ZY
6 cm -- YX
7 cm -- XZ

And for the other triangle, ...

6 cm -- BC
12 cm -- AB
14 cm -- AC

<h3>corresponding vertices</h3>

The points joining the each side to the next one longer, in order for the two triangles, are ...

Y, X, Z and B, A, C

The vertices corresponding to ZYX in the same order are CBA.

triangle ZYX is similar to triangle CBA

3 0

2 years ago

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