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Otrada [13]
3 years ago
11

Midpoint (2,5) (-1,9)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

The midpoint of the 2 points is (0.5, 7)

Hope this helps you

-AaronWiseIsBae

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Help plzzzz I need help ASAP thank you
pentagon [3]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
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A polygon has the following coordinates: A(-4,-3), B(4,-3), C(4,-7), D(-4,-7). Find the length of BC.
KIM [24]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
Can the side lengths of 8, 9, and 12 form a triangle?
Rama09 [41]

Answer:

No

Step-by-step explanation:

The formula you could do to check would be 8^2+9^2=12^2.

In this instance, 8^2 + 9^2 = 145 but 12^2 equals 144

7 0
3 years ago
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A die is rolled 30 times. How many times can you expect it to land on a number less than 5?
erma4kov [3.2K]

Answer:

5/6 is your answer

Step-by-step explanation:

no. of favourable observation/ total no of observation

6 0
3 years ago
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