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3 years ago

Brads scooter uses 1/4 gallon of fuel each mile. If Brad drives 2 miles. How much fuel does he use?

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Brad would use 1/2 gallon of fuel
1/4 per mile × 2 miles= 1/2 gallon of fuel

EleoNora [17]3 years ago

8 0

If 1 mile = 1/4 then you need to double this for 2 miles

1/4 + 1/4 = 1/2

So he uses 1/2 a gallon

You might be interested in

Find the probability of having 2, 3, or 4

denis-greek [22]

Answer:

16% for 2 successes, 6.4% for 3 successes, 2.6% for 4 successes, and 1% for 5 successes

Step-by-step explanation:

Since the success rate of a binomial experiment is 40%, converted to 0.4, you get the equation of f(x) = (0.4)^x, for where x is the amount of successful experiments

For the success of 2 experiments:

f(2) = (0.4)^2

=0.16 => 16%

For the success of 3 experiments:

f(3) = (0.4)^3

= 0.064 => 6.4%

For the success of 4 experiments:

f(4) = (0.4)^4

= 0.0256 => 2.56% => ~2.6

For the success of 5 experiments:

f(5) = (0.4)^5

= 0.01024 => 1.024% => ~1%

Your welcome and comment if you have any questions :)

3 0

3 years ago

What is the base? Area= 9/10 Height=3/5 PLEASE HELP ME!!

Phantasy [73]

AREA= 1/2 BASE * HEIGHT
9/10 = 1/2x*3/5
x= 9/10*10
x=9
Thus, the base is 9

8 0

3 years ago

OK before from the playing golf. The total cost of the round of golf is $108. Each person in the group has the same coupon. The

Fantom [35]

108 - 76 = 32

so your answer is, it's worth $32

8 0

3 years ago

Is 1/4 the answer to this what ratio forms a porportion with 8/36

Svetlanka [38]

No.
1/4 would be proportional to 9/36.

8/36 can be simplified to 4/18, and further reduced to 2/9.

3 0

3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

3 years ago