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4 years ago

To ship a package, a shipping company charges $2.74 for each pound. How much would it cost to ship a 6.7-pound package?

Mathematics

1 answer:

Olin [163]4 years ago

3 0

I'm pretty sure this would be 18.358

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Helppppppppppppooppppoopp

Lyrx [107]

Answer:

Let x rep the lenght of the shorter one

Then the longer one is 2x+1

Therefore

(2x+1) + x = 16

We now solve for x

2x + 1 + x = 16

Group and evaluate like terms

3x +1 = 16

3x = 16 -1

× = 15/3

x = 5

So the shorter one is 5 ft

The longer one is 2(5)+1= 11

4 0

3 years ago

Heather opens a bank account with $125. Each week, starting the following week, she deposits $25 into her account.

Rufina [12.5K]

Total money in account=125+25n

7 0

4 years ago

Read 2 more answers

While mining, Keith found a large metal bar that weighed 42 ounces. Keith was also able to determine that the bar had 30 ounces

Usimov [2.4K]

Divide the silver present in the bar by the total weight of the bar to find the percentage of silver in the bar.

$30 / 42 = 0.7142$

Multiply this decimal by 100 for the percentage.

$.7142 * 100 = 71.42$

Rounded to the nearest tenth, 71.4% of the weight of the bar is silver.

8 0

4 years ago

Read 2 more answers

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a Poisson process at the rate of 5.5 per hour and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$

and we want P(X ≥ 75) = 1-P(X<75). But

$\bf P(X$

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0

4 years ago

Which of the following equations is written in vertex form?

ivanzaharov [21]

The third one is correct.

3 0

3 years ago