Find the missing segment in the attached image

Mathematics

1 answer:

uranmaximum [27]3 years ago

6 0

Answer:

25 units

Step-by-step explanation:

This problem can be solved by using concept of Basic proportionality theorem.

This theorem states that if there is line drawn parallel to any side of the triangle, and it intersect the other two sides, then

segment divided on those two sides are in equal proportion.

Let naem this triangle

the side containing 15 and 6 be AB, with A be point on segment having length 15 units

B be point on segment having length 6 units

c be point on segment having length ? units

DE line parallel to BC

Thus, if apply Basic proportionality theorem. in this then ratio formed will be

15/6 = ?/10

5/2 = ?/10

?= 5/2* 10 = 25

The length of missing segment is 25 units.

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Write each ratio as a fraction in the lowest terms

stich3 [128]

Answer:

1/4

Step-by-step explanation:

$(4\times \frac{3}{8} ) : (12\times \frac{1}{2} )\\\\\frac{4\times \frac{3}{8}}{12\times \frac{1}{2}}\\\\\mathrm{Multiply\:}12\times \frac{1}{2}\::\quad 6\\=\frac{4\times \frac{3}{8}}{6}\\\\\mathrm{Multiply\:}4\times \frac{3}{8}\::\quad \frac{3}{2}\\=\frac{\frac{3}{2}}{6}\\\\=\frac{3}{2\times \:6}\\\\=\frac{3}{12}\\\\=\frac{1}{4}$