3 years ago

I need help on the problem #53 it asking to prove if it is an identity.

Mathematics

1 answer:

pav-90 [236]3 years ago

8 0

Answer and workings can be found in the attachment below...

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Suppose 5 out of every 18 of the people who like to work out have a gym membership. At the same rate, in a group of 216 people,

Jlenok [28]

Answer:

60 people

Step-by-step explanation:

Set up a proportion:

$\frac{5}{18}$ = $\frac{x}{216}$

Cross multiply and solve for x:

18x = 1080

x = 60

So, 60 people would have a gym membership

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

******ANSWER ASAP PLEASE******

Lemur [1.5K]

(1/4)^-2 - (5^0 x 2) x 1^-1 =

(4/1)^2 - (1 x 2) x 1 = 16-2 = 14

If you raise something to the power of -2, swap numerator and denominator and remove the minus.

So (1/4)^-2 = 4^2 = 16

Also 1^-1 is just 1, not -1.

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

5 2/5 more than a number is 7 1/2

Citrus2011 [14]

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Step-by-step explanation:

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4 years ago

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