so the ODE is indeed exact and there is a solution of the form 
. We have
With 
, we have
so
Answer:
m IHE = 134°
Step-by-step explanation:
.
Since, DF || GI
so, m GHJ = m IHE
( vertical opposite angles )
m IHE = 134°
F'(x)=-2x{e^(-x²)}
Equating f'(x)=0,
i.e,
-2x{e^(-x²)}=0....eqn(i)
For maximum slope:
Differentiating (i) wrt x,we get,
4x² {e^(-x²)}-2 {e^(-x²)}=0
{e^(-x²)} [4x²-2]=0
4x²-2=0
x=1/√2
If f(x)=y then f'(x)=dy/dx=slope
So,
Maximum slope
= f'(x)
= -2x{e^(-x²)}
=-2×(1/✓2){e^(-1/✓2)²}
= -✓2{e^(-1/2)}
=(-sqrt 2/sqrt e)
=-sqrt(2/e)➡c is correct
Answer:
1) 24
2) 24
3) b. 9n +5
Step-by-step explanation:
1) substitute
4(7) + 2(-2)
solve
28 + -4
24
2) substitute
P = (2)(3)(4)
multiply
24
4) im not sure, my apologies
5) i'm not sure, i don't understand what's being asked, if you rephrase this, i can give you an answer
have a lovely day <3
X^2 2x + 1 = (x + 1)^2
x is replaced by x + 1
the translation is 1 unit to the left
