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san4es73 [151]
3 years ago
6

A pyramid composed of four equilateral triangles, called a tetrahedron, has a one-side length of 5 meters. What is its surface a

rea? Round the answer to the nearest tenth.
____ square meters.

A) 125.0
B) 43.3
C) 68.3
Mathematics
1 answer:
natulia [17]3 years ago
8 0
The surface area of a regular tetrahedron is computed as the product of  √3 and the square of the length of one side. The length given is 5 meters, by evaluating, we will have A = √3 (a²) = √3 (25) = 43.30. The answer is B.
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Which point is an x-intercept of the quadratic function

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A new truck that sells for $29,000 depreciates 12% each year. Which function models the value of the truck?
ladessa [460]
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3 years ago
The ratio of the measures of the sides of a triangle is 3:4:5. Its perimeter is 48 inches. Find the scale factor as a decimal, a
Trava [24]

Given:

The ratio of the measures of the sides of a triangle is 3:4:5.

Its perimeter is 48 inches.

To find:

The scale factor as a decimal, and the measure of each side of the triangle.

Solution:

Let x be the scale factor. Then the measures of sides of the triangle are 3x, 4x and 5x.

The perimeter of the triangle is 48 inches. It means the sum of all sides of the triangle is 48 inches.

3x+4x+5x=48

12x=48

Divide both sides by 12.

x=\dfrac{48}{12}

x=4

Now, the measures of sides are:

3x=3(4)

3x=12

Similarly,

4x=4(4)

4x=16

And,

5x=5(4)

5x=20

Therefore, the scale factor is 4 and the measures of sides are 12, 16 and 20.

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