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lorasvet [3.4K]

3 years ago

8

the units digit of a two digit number is 10. If the digits are reversed, the new number is 9 less than the original number. find

the original number

1 answer:

Irina-Kira [14]3 years ago

4 0

Answer: the units digit has to be a 1 digit number not 2

Step-by-step explanation:

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mafiozo [28]

True by side angle side. You already have 2 congruent sides, so then do right angles congruence theorem to get the angles are congruent

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3 years ago

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JulsSmile [24]

Answer:

y=2x+b

Step-by-step explanation:

7 0

2 years ago

a rectangle is 5 inches long and 2x inches wide. The value of the perimeter is 22 inches what is the value of x?

Alekssandra [29.7K]

Answer: x =3

Step-by-step explanation:

2× 3 = 6

length= 5 inches

width= 2×3= 6 inches

2(l+w) = 2(5+6)

2(11)

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hope this helps:-)

4 0

3 years ago

What is the midpoint M of that line segment?

topjm [15]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ T(\stackrel{x_1}{6}~,~\stackrel{y_1}{3})\qquad U(\stackrel{x_2}{6}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+6}{2}~~,~~\cfrac{9+3}{2} \right)\implies \left( \cfrac{12}{2}~~,~~\cfrac{12}{2} \right)\implies \stackrel{M}{(6,6)}$

3 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago