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horrorfan [7]
3 years ago
14

Solve A=1/2bh for b how do i solve this

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0
You would start of by doing
A=1/2bh
—. ——. <—-Divide
B. B

After that you will end up with
AB=1/2H

Then isolate the B by dividing both sides by A

AB=1/2h
—- ——
A. A

Which will leave you with your answer of

B=1/2ha or B=1/2ah


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The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
3 years ago
Lin runs 5 laps around a track in 8 minutes.
andrezito [222]

Answer:

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Step-by-step explanation:

To find this answer you would do 8 divided by 5. Always remember when dividing time goes first unless the instructions / directions / your teacher says differently. So, when you do 8 divided by 5 the answer you get is 1.6, and there is your answer. Also to check your answer you can do 1.6 times 5, and you get 8, so you know that 1.6 is the correct answer.

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uranmaximum [27]

Answer:

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Pair like terms

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4 0
3 years ago
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\bf \cfrac{x^2+6x-9}{x-2}\qquad &#10;\begin{cases}&#10;x^2\impliedby \textit{has a degree of 2}\\&#10;x^1\impliedby \textit{has a degree of 1}&#10;\end{cases}

if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.
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3 years ago
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