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Alex73 [517]
3 years ago
14

What equation can relate to this sentence 11 is the quotient of a number y and 6 ?

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer: 11 = y ÷ 6

Step-by-step explanation: since the problem says 11 is that means the equation equals 11 and when it says quotient that means that the equation must include division.

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Answer:

he's right its D

Step-by-step explanation:

3 0
3 years ago
Frank invests $1,000 in simple interest investment account that pays 8% a year. After a number of years, he withdraws his balanc
elena-s [515]

Answer:

15 years

Step-by-step explanation:

Given data

P=$1,000

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I=PRT/100

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cross multiply

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divide both sides by 8000

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6 0
2 years ago
one days discharge at its mouth, 3 trillion gallons, could supply all of country A’s household for 5 months. how much water an a
serious [3.7K]

let's use engineering notation for the sake of brevity.

1 trillion is 1,000,000,000,000, or just 1E12, twelve zeros.

1 million is then 1E6, six zeros.

we know the discharge for one day is 3E12 gallons, and that'd do just fine for country A for 5 months.  How many gallons in 1 month only?

\bf \begin{array}{ccll} gallons&months\\ \cline{1-2} 3E12&5\\ x&1 \end{array}\implies \cfrac{3E12}{x}=\cfrac{5}{1}\implies 3E12=5x \\\\\\ \cfrac{3E12}{5}=x\implies 6E11=x\implies 600000000000=x

if there are 200million inhabitants in A, namely 200E6 or 2E8 inhabitants, how many gallons per inhabitant from all those 6E11 gallons?

\bf \begin{array}{ccll} gallons&households\\ \cline{1-2} 6E11&2E8\\ x&1 \end{array}\implies \cfrac{6E11}{x}=\cfrac{2E8}{1}\implies 6E11=2E8x \\\\\\ \cfrac{6E11}{2E8}=x\implies \cfrac{600000000000}{200000000}=x\implies 3000=x

5 0
3 years ago
Which shows a correct order to solve this story problem?
RSB [31]
The correct answer is C because since you want to find the totally of both of the together you would add
8 0
3 years ago
Read 2 more answers
....................
4vir4ik [10]
Using the ratio 4/2 = 2
 and 8/4 = 2

 so they are similar because 4/2 equals 8/4

6 0
3 years ago
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