Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
1)73 degrees
all the angles of a triangle add up to 180 degrees.
23+84= 107
180-107=73
2) 28 degrees
110+42= 152
180-152= 28
Answer:
5x^2−10x−2
Step-by-step explanation:
I hope this is what you are looking for I just added (5x^2 – 9) + (-10x + 7)
Answer:DEFINITELY B
THE PROOF IS IN YOUR BIBLE
Step-by-step explanation:
Answer:
What did Timmy want for Christmas? parents, What did Timmy get for Christmas? tuberculosis
:)
Step-by-step explanation:
