The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Learn more about perimeter of a rectangle here:
brainly.com/question/16715918
Sorry if it's wrong, I tried
Answer:
MAD = 0
Step-by-step explanation:
When I calculated this by hand I got 0. To find the MAD:
1. You first need to find the mean of the numbers.
4 + 5 + 8 + 8 + 10 = 35
35/5 = 7
the mean value = 7
2. Then you must find the absolute value of the difference between each data value and the mean: |data value – mean|
(4 - 7) = -3
(5 - 7) = -2
(8 - 7) = 1
(8 - 7) = 1
(10 - 7) = 3
3. Add the difference values up
(-3) + (-2) + 1 + 1 +3 = 0
4. Divide the sum of the absolute values of the differences by the number of data values.
0/5 = 0
Move all terms not containing x to the right side of the equation
x=9
Answer:
13.5
Step-by-step explanation:
5.5+8=13.5
