Question

The length of a rectangle is 3 inches more than its width. The perimeter of the rectangle is 34 inches. The length of the rectangle is inches, and its width is inches.

Answer 1

L=3+w
w=w
p=2(3+w)+2w
p=6+2w+2w
p=6+4w
34=6+4w
28=4w
w=7
l=10

Answer 2

Answer:

The width of rectangle is 7 inches.

The length of rectangle is 10 inches.

Step-by-step explanation:

Let w represent width and l represent length of the rectangle.

We have been given that the length of a rectangle is 3 inches more than its width. We can represent this information in an equation as:

$l=w+3...(1)$

We are also told that the perimeter of the rectangle is 34 inches. We know that perimeter of a rectangle is two times its width and length. We can represent this information in an equation as:

$2(w+l)=34...(2)$

Upon substituting equation (1) in equation (2), we will get:

$2(w+w+3)=34$

$2(2w+3)=34$

Using distributive property $a(b+c)=ab+ac$, we will get:

$2*2w+2*3=34$

$4w+6=34$

$4w+6-6=34-6$

$4w=28$

$\frac{4w}{4}=\frac{28}{4}$

$w=7$

Therefore, the width of rectangle is 7 inches.

Upon substituting $w=7$ in equation (1), we will get:

$l=w+3$

$l=7+3$

$l=10$

Therefore, the length of rectangle is 10 inches.