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Ilya [14]
3 years ago
5

How many of each angles are in a pentagon

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

There are 108 degrees in each interior angle of a regular pentagon .


I hope that's help !

tamaranim1 [39]3 years ago
5 0
The Answer to this question is:108 degrees.
hope this helps! (:
You might be interested in
Please help me 33/2 + 3y/5 = 7y/10 + 15
8090 [49]

We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

8 0
2 years ago
2c + 7.5 = 6.2 - 3c a. 0.26 b. -0.26 c. -2.74 d. 1.3
Maurinko [17]

b

5c=6.2-7.5

then divide it :)

6 0
2 years ago
A school spent $2,587.50 on agendas for its 1,150 students. what is the unit price per agenda
damaskus [11]

For this you can just use a calculator and divide 2587.5 by 1150.

You should get $2.25 for the unit price. Hope this helped ^-^

7 0
3 years ago
Bill earned $10.00 per hour. He worked 40 hours at regular rate, 2 hours at time and a half
Verizon [17]

Answer:

400.00

Step-by-step explanation:

is that what you meen ?

8 0
3 years ago
Read 2 more answers
The population of big cats in Africa is increasing at a rate of 5% per year. At the
sesenic [268]

Answer:

a) 10,500 big cats

b) 13,401 big cats

c) 33 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:  

A = P (1 + r) t  

Where:  

p = original population  

r = growing rate (decimal form; 5/100= 0.05)

t= years  

A = population after t years  

Replacing with the values given:  

a) At 2005, 1 year passed since 2004 (t=1)

A = 10,000 (1+ 0.05)^1

A = 10,500 big cats

b)

At 2010, 6 years passed since 2004 (2010-2004= 6)

A = 10,000 (1+ 0.05)^6

A = 13,401 big cats

c)

50,000 < 10,000 (1+ 0.05)^t

Solving for t:

50,000/10,000 < 1.05^t

5 < 1.05^t

log 5 < log 1.05^t

log 5 < t ( log 1.05)

log 5 / log 1.05 < t

32.9 years < t

33 years  = t

Feel free to ask for more if needed or if you did not understand something.  

6 0
3 years ago
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