Answer: Keyboard hardware & the operating system
Explanation:Keystroke loggers is also referred as the monitoring system which is a for the inspection of the every key pressed on an operating system. This technology monitors the activities of keypad devices such as smart phones etc. It is also used for the surveillance of the unauthorized activities that are done by the hackers or criminals.
Thus the correct option is keyboard hardware and the operating system is the location of the placement of the key loggers.
Answer:
i would say Plane, if not then Plane then the person's birthdate.
Explanation:
Wow!! that is ALOT of info,I dont think i could help with this one Umders 699 maybe someone else can sorry that i couldn`t help :)
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
