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DiKsa [7]
3 years ago
13

Find the volume of a right circular cone that has a height of 9.1 m and a base with a circumference of 12.1 m. Round your answer

to the nearest tenth of a cubic meter.
Mathematics
1 answer:
Orlov [11]3 years ago
7 0

Answer:

V=35.3\ m^3

Step-by-step explanation:

-Given the cone's height is 9.1m and the Circumference is 12.1

#We use the circumference formula to calculate the radius:

C=2\pi r\\\\12.1=2\pi r\\\\r=\frac{12.1}{2\pi}=\frac{6.05}{\pi}\ cm

-The volume of the cone using the radius above can then be calculated as follows:

V=\pi r^2\frac{h}{3}\\\\=\pi\times(\frac{6.05}{\pi})^2\times \frac{9.1}{3}\\\\\\=35.3\ m^3

Hence, the cone's volume is 35.3\ m^3

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We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:

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Now, subtract 19 from both sides:

x < 23

Our number can be anything less than 23.
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Step-by-step explanation:

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shtirl [24]

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docker41 [41]
<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =

factoring with leading coefficient:

for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
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replace bx with mx + nx and factor by grouping
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answer:
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