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fenix001 [56]
3 years ago
6

A test contains two multiple-choice questions. If a student makes a random guess to answer each question. (Hint: Consider two ou

tcomes for each question—either the answer is correct or it is wrong.) 2.2.1 How many outcomes are possible?
Mathematics
1 answer:
Maslowich3 years ago
5 0

Answer: 2

Step-by-step explanation: he could ethier get t right or get it wrong

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Complete the equation so it has infinitely many solutions.
suter [353]

Answer:

im not sure

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the quotient of 812.30 divided by 83. Round to the nearest tenth.
elena-14-01-66 [18.8K]
812.30/83 = 9.78674698.....
Nearest tenth means one number under decimal place so...

812.30/83 ~ 9.8

Explanation: The 9.7... rounded up to 9.8 because the number after the tenths place (in this case the number after the 7) is greater or equal to 5.
7 0
3 years ago
How do i find the surface area of a cylinder with a radius of 3.5 ft. and a height of 14 ft.
Karolina [17]
The formula for the surface area of a cylinder is:
2<span>π</span><span>r</span><span>h </span><span>+ </span><span>2</span><span>π</span><span>r^</span><span>2

If we substitute in the measurements that we know, you get:

2</span><span>\pi (3.5) (14) + 2</span><span>\pi (3.5)^2

If we simplify this expression, we get:

98</span><span>\pi + 24.5</span><span>\pi

If you simplify once more, you get

122.5</span><span>\pi or </span><span>≈ 384.85

Therefore, the surface area is 122.5</span>\pi or about 384.85<span>


</span>

3 0
3 years ago
The circular opening of a tunnel has a circumference of 36 meters. What is the diameter of the tunnel?
Elza [17]
C=2(3.14159...)R
You’re given the circumference, so all you need to do is plug that in and simplify.
36=2(3.14159...)R
36=6.28R
36/6.28=R
R is about 5.73
7 0
3 years ago
Please help me with this!<br><br><br> show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}
Llana [10]

The set \{x\mid x^4-x^3-x^2-6x+6=0\} is the set of all values of x that are solutions to the given equation. So all you need to do is check whether x=1 and x=2 satisfy the equation.

x=1\implies 1^4-1^3-1^2-5+6=0

x=2\implies2^4-2^3-2^2-10+6=0

The equation holds, so both 1 and 2 are solutions, and hence \{1,2\} is a subset of the solutions.

6 0
3 years ago
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