Answer:
Bob drove from home to work at 75 mph. After work the traffic was heavier, and he drove home at 40 mph. His driving time to and from work was 1 hour and 9 minutes. How far does he live from his job?
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Avg speed for the round trip = 2*75*40/(75+40) = 6000/115 = 1200/23 mi/hr
RT distance = 1200/23 * 69 minutes * 1 hr/60 mins =
= 60 miles
30 miles each way
Step-by-step explanation:
Answer:
Step-by-step explanation:
That'd be the second root of 7^3, where 3 is the exponent of the radical.
Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.
x - 3 ≤ 0
x + 5 ≤ 0
For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.
x ≤ 3
x ≤ - 5
These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.
Chuck travels at A) 30 mph
since chuck and dana travelled at the same amount of time (2 hours), dana travels at 26 mph, which is 4 mph less, and chuck travels at 30.
Answer:
Her speed is of 2 miles per hour.
Step-by-step explanation:
Velocity:
The velocity is given by the following formula:
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
In which v is the velocity, d is the distance and t is the time.
2/3 mile in 1/3 hour .
This means that ![d = \frac{2}{3}, t = \frac{1}{3}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B2%7D%7B3%7D%2C%20t%20%3D%20%5Cfrac%7B1%7D%7B3%7D)
Which unit rate describes antoinettes speed in miles per hour?
This is v. So
![v = \frac{d}{t} = \frac{\frac{2}{3}}{\frac{1}{3}} = \frac{2}{3}*\frac{3}{1} = 2](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B2%7D%7B3%7D%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%2A%5Cfrac%7B3%7D%7B1%7D%20%3D%202)
Her speed is of 2 miles per hour.