=(D-64)2
We move all terms to the left:
-((D-64)2)=0
We calculate terms in parentheses: -((D-64)2), so:
(D-64)2
We multiply parentheses
2D-128
Back to the equation:
-(2D-128)
We get rid of parentheses
-2D+128=0
We move all terms containing D to the left, all other terms to the right
-2D=-128
D=-128/-2
D=+64
Let the no be X and Y
acc to ques....
x-y=9 .........1
xy=162 ..........2
substituting value from 1 in 2 we get;
x=9+y
[9+y][y] = 162
y^2+9y = 162
y^2 + 9y - 162=0
y^2 + 18y - 9y - 162=0
y[y+18] + 9[y+18]=0
[y+9][y+18}
y= -9.................................3
y= -18......................................4
case 1 :
y= -9
x = 9-9=0
case 2:
y= -18
x= 9-18 = -9
C.(x-2)^2+(y+10)^2=9, plug the numbers in the original formula.
Answer:
The side length is multiplied by 6.
Step-by-step explanation:
The area of a square is A = s². Suppose the side is 8 inches. This means the area is A = 8² = 64.
If you were to multiply by 36, then it becomes 64*36 = 2,304. Since squaring gave the area, it's side length would be found using the reverse operation a square root. Take the square root of 2,304.
√2304 = 48
The side length changed from 8 to 48 which is a scale factor of 6. This means 8 * 6 = 48.
Multiply each term in the parentheses by 3. Your answer is 6a - 12b
