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fomenos
3 years ago
15

Name the points which satisfy the conditions. The ordinate is zero.

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0

9514 1404 393

Answer:

  G

Step-by-step explanation:

The one point with a y-value of 0 is the one on the x-axis: G.

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Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
A patient is ordered 10 units of Drug B per kg of body weight
Lostsunrise [7]

answer.

It will be 750 units

Step-by-step explanation:

we multiply the ten by sevety five and the answer is 750

3 0
2 years ago
17) The total cost to produce x units of paint is C(x) = (5x + 3)(7x + 4). Find the marginal
Bad White [126]

Answer:

17) MC(x) = 35 − 12/x²

18) R(x) = -0.05x² + 80x

Step-by-step explanation:

17) The marginal average cost function (MC) is the derivative of the average cost function (AC).

AC(x) = C(x) / x

MC(x) = d/dx AC(x)

First, find the average cost function:

AC(x) = C(x) / x

AC(x) = (5x + 3)(7x + 4) / x

AC(x) = (35x² + 41x + 12) / x

AC(x) = 35x + 41 + 12/x

Now find the marginal average cost function:

MC(x) = d/dx AC(x)

MC(x) = 35 − 12/x²

18) x is the demand, and p(x) is the price at that demand.  Assuming the equation is linear, let's use the points to find the slope:

m = (40 − 50) / (800 − 600)

m = -0.05

Use point-slope form to find the equation of the line:

p(x) − 50 = -0.05 (x − 600)

p(x) − 50 = -0.05x + 30

p(x) = -0.05x + 80

The revenue is the product of price and demand:

R(x) = x p(x)

R(x) = x (-0.05x + 80)

R(x) = -0.05x² + 80x

7 0
4 years ago
What is the volume of this rectangular prism?
Leni [432]

Answer:

20

Step-by-step explanation:

cause 2/3 * 6 is 4 then 4*5 is 20

6 0
3 years ago
Hazel wants to mix 12 pounds of her special blend coffee that will cost her $12.50 per pound. She uses Columbian and Sumatra cof
k0ka [10]
Let x be the amount of Columbian coffee in the mixture and y the amount of Sumatra coffee in the mixture, then
x + y = 1 . . . (1)
9.25x + 14.25y = 12.50 . . . (2)

(1) x 9.25 => 9.25x + 9.25y = 9.25 . . . (3)

(2) - (3) => 5y = 3.25 => y = 3.25/5 = 0.65

From (1), x + 0.65 = 1 => x = 1 - 0.65 = 0.35

1 pound of the mixture contains 0.35 Columbian coffee and 0.65 Sumatra coffee
Therefore, 12 pounds of the mixture will contain 0.35 x 12 = 4.2 pounds of Columbian coffee and 0.65 x 12 = 7.8 pounds of Sumatra coffee
3 0
3 years ago
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