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Komok [63]
3 years ago
5

PLEASE HELP THIS IS A TIMED TEST!!!!! I WILL GIVE BRAINLIEST TO THE FIRST GOOD ANSWER IF YOU ASK FOR BRAINLIEST BEFORE ANSWERING

YOU WILL BE REPORTED

Mathematics
2 answers:
Anna [14]3 years ago
7 0

Answer:

x=allrealsoulutions

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

6x-15=6x-15

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What is the exact distance from (-5, 1) to (3,0)? (4 points)
frez [133]

Answer:

The exact distance is √65 units

Step-by-step explanation:

To solve this problem we first have to make the difference between (-5, 1) and (3, 0)

(3 , 0) - (-5 , 1) =

3 - (-5) = 8

0 - 1 = -1

(8 , -1)

Now that we have the distance in x and r we can use Pythagoras to calculate the distance of the diagonal

a = 8

b = -1

h² = a² + b²

h² = 8² + (-1)²

h² = 64 + 1

h² = 65

h = √65

The exact distance is √65 units

4 0
3 years ago
Its math again so sorry
igor_vitrenko [27]

Answer:

589

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the system of equations for X.<br> X+ 2y= 24<br> 2x+y= 9
Phantasy [73]

Answer:

c) because i did it on usa tp -13 and listen to ariana grande position great for school thinking

Step-by-step explanation:

if you do 2x11+-13=9    11+2x-13=24

6 0
3 years ago
What acceleration will result when a 12 N force is applied to a 6 kg object?
masha68 [24]

Hi there!

\large\boxed{2 m/s^{2}}

Use the equation F = m · a where:

F = Force (N)

m = mass (kg)

a = acceleration (m/s²)

Plug in the given values:

12 = 6a

Divide both sides by 6:

12/6 = a

a = 2 m/s²

3 0
3 years ago
Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
6 0
3 years ago
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