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3 years ago

Help with this I don't know how to solve

Mathematics

1 answer:

Gnesinka [82]3 years ago

4 0

Answer:

The right answer is the first option, $tg= \frac{\sqrt{105}}{4}$

Step-by-step explanation:

The tg is the ratio of the opposite cathet to the adjacent cathet .

Here b is the opposite cathet, с is the hypotenuse and b is an adjacent cathet.

$tg = \frac{b}{a}$

Let's find b.

$c^2=a^2+b^2\\ b^2=c^2-a^2\\ b^2=22^2-8^2\\ b^2=484-64\\ b^2=420\\ b=\sqrt{420} = \sqrt{2*21*2*5} = 2\sqrt{105}$

Now let's find tgθ.

$tg = \frac{b}{a} \\ tg = \frac{2\sqrt{105}}{8} \\ tg=\frac{\sqrt{105}}{4}$

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2 years ago

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Step-by-step explanation:

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3 years ago

2. If x is directly proportional to y^3 and x=32 when y=2, i) Find an equation

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Answer:

(i)

$x \alpha y {3} \\ \frac{x}{y {3} } = k$

(ii)

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2 years ago

Someone help me with this ples with steps

SSSSS [86.1K]

Answer:

$x=\frac{21}{4}$

$y=\frac{21}{2}$

Step-by-step explanation:

equation (1): $\frac{1}{2} (2x+y)=\frac{21}{2}$

equation (2): y=2x

solve the system by substitution

step1: sub (2x) for y in equation 1:

$\frac{1}{2} (2x+y)=\frac{21}{2}$

$\frac{1}{2} (2x+2x)=\frac{21}{2}$

step2: simplify the expression:

$\frac{1}{2} (4x)=\frac{21}{2}$

$2x=\frac{21}{2}$

(divide by 2 for both sides)

$x=\frac{21}{4}$

To find the value for y sub 21/4 for x in equation 2:

y=2x

y=2×(21/4)

$y=\frac{21}{2}$

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3 years ago

An arithmetic sequence has t1=5 and t2=8 find tn and sn

RoseWind [281]

Answer:

$a_n=2+3n$

$\displaystyle S_n=\frac{7n+3n^2}{2}$

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

$a_n=a_1+(n-1)r$