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kari74 [83]
3 years ago
12

Help!! 2(3x+4y)=4x+12y

Mathematics
2 answers:
katrin2010 [14]3 years ago
5 0

Answer: x = 2y

Step-by-step explanation:

Let's solve for x.

2(3x+4y)=4x+12y

Step 1: Add -4x to both sides.

6x+8y+−4x=4x+12y+−4x

2x+8y=12y

Step 2: Add -8y to both sides.

2x+8y+−8y=12y+−8y

2x=4y

Step 3: Divide both sides by 2.

<u>2x </u>

2

=

<u>4y </u>

2

x=2y

Answer:

x=2y

aalyn [17]3 years ago
3 0

<em>Solve</em><em> </em><em>for</em><em> </em><em>x</em><em> </em>

<em>2</em><em> </em><em>(</em><em> </em><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>4</em><em>y</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>4</em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em>2</em><em>y</em><em> </em>

<em>6</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em><em>y</em><em> </em><em>=</em><em> </em><em>4</em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em>2</em><em>y</em><em> </em>

<em>6</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em><em>y</em><em> </em><em>-</em><em> </em><em>4</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>y</em><em> </em>

<em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em><em>y</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>y</em><em> </em>

<em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>y</em><em> </em><em>-</em><em> </em><em>8</em><em>y</em><em> </em>

<em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>4</em><em>y</em><em> </em>

<em>2</em><em>x</em><em> </em><em>/</em><em> </em><em>2</em><em> </em><em>=</em><em> </em><em>4</em><em>y</em><em> </em><em>/</em><em> </em><em>2</em><em> </em>

<em>x</em><em> </em><em>=</em><em> </em><em>4</em><em>y</em><em> </em><em>/</em><em> </em><em>2</em><em> </em>

<em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>y</em><em> </em>

<em>Sorry</em><em> </em><em>if</em><em> </em><em>I'm</em><em> wrong</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

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